[Templates] differentiating hash entries / methods with same name

Tue, 7 Nov 2006 14:47:04 +0100

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Hi all,

Suppose an object $obj has both a hash entry $obj->{foo} and a method
$obj->foo().

If I pass this object to a template,  [% obj.foo %] performs a method
call.

 Is there a way to access the hash entry instead?

Thanks in advance, L. Dami

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<P><FONT SIZE=3D2 FACE=3D"Arial">Hi all,</FONT>
</P>

<P><FONT SIZE=3D2 FACE=3D"Arial">Suppose an object $obj has both a hash =
entry $obj-&gt;{foo} and a method $obj-&gt;foo().</FONT>
</P>

<P><FONT SIZE=3D2 FACE=3D"Arial">If I pass this object to a =
template,&nbsp; [% obj.foo %] performs a method call.</FONT>
</P>

<P><FONT SIZE=3D2 FACE=3D"Arial">&nbsp;Is there a way to access the hash =
entry instead?</FONT>
</P>

<P><FONT SIZE=3D2 FACE=3D"Arial">Thanks in advance, L. Dami</FONT>
</P>

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